5y^2-24y/4=0

Solution for 5y^2-24y/4=0 equation:

5y^2-24y/4=0

We multiply all the terms by the denominator


5y^2*4-24y=0

Wy multiply elements

20y^2-24y=0

a = 20; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·20·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*20}=\frac{0}{40}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*20}=\frac{48}{40}
=1+1/5
$